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In a bag, there are 17 red balls, some green, and some blue balls. The probability of drawing a green ball is (1/7) more than that of a red ball. The probability of drawing a blue ball is (1/21) more than that of a red ball.
Find the total number of balls in the bag
91
84
63
none of these
cannot be determined
Correct option 3: 63
Let the number of green balls and blue balls present in the bag be 'g' and 'b' respectively Also, number of red balls = 17 Total number of balls = (17+ g + b) Probability of drawing a red ball = 17/(17+ g + b) Probability of drawing a green ball = g/(17+g+b) Probability of drawing a blue ball = b/(17+g+b) Now a/q we have ⇒g/(17+g+b) = 1/7+17/(17+g+b) (g-17)/(17+g+b) = 1/7 6g-b =136 .....(1) also, ⇒b/(17+ g + b) = 1/21 + 17/(17+g+b) ⇒(b-17)/(17+ g + b) = 1/21 20b - g = 374 ....(ii) using equation (i) and (ii), we get g = 26, b = 20 .. Required total number of balls in the bag = (26 +20 +17) = 63
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