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Directions: Read the given table carefully and answer the following questions. Given table shows the Quantity of milk distributed by milkman and the quantity of milk and water added and the quantity left after adding water and milk. Some values are missing here. A milkman have 'X' litre of milk and water mixture in the ratio 5 : 1. He gives milk to three persons Amit, Gareema and Madhu.
Persons Quantity given to Client (in L) Quantity of milk added (in L) Quantity of water added (in L) Quantity left after adding water and milk (in L)
Amit 120 80 0 560
Gareema y 60 10 M
Madhu 200 3r r z
Data calculated from solving one part can be used in the calculation of the other part.
Find the value of 'X'.
200
720
600
360
300
Let's solve step-by-step:
- The milkman starts with a mixture (X litres) in the ratio 5:1 (milk:water).
- He distributes to Amit (120L), Gareema (y L), Madhu (200L).
- After each distribution, milk and/or water is added, and the quantity left ("after") is given.
---
Let's check Amit’s row:
- Given: 120L to Amit.
- 80L milk added, no water.
- After = 560L.
So, before adding, amount left = 560 – 80 = 480L.
Total given so far = 120L.
So, 480 + 120 = 600L was there just before Amit got milk, so X = 600 litres.
All Options Explained:
- Option 1, 200L – Too low, doesn't fit data.
- Option 2, 720L – No, would require more distributed milk or additions.
- Option 3, 600L – This fits precisely as shown above.
- Option 4, 360L – Too low, can't account for remaining.
- Option 5, 300L – Too low, can't reach what's left after serving Amit.
Conclusion:
- Option 3 (600L) is correct.
-
Correct Option: 3 – 600
By: Parvesh Mehta ProfileResourcesReport error
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