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Directions: Read the given table carefully and answer the following questions. Given table shows the Quantity of milk distributed by milkman and the quantity of milk and water added and the quantity left after adding water and milk. Some values are missing here. A milkman have 'X' litre of milk and water mixture in the ratio 5 : 1. He gives milk to three persons Amit, Gareema and Madhu.
Persons Quantity given to Client (in L) Quantity of milk added (in L) Quantity of water added (in L) Quantity left after adding water and milk (in L)
Amit 120 80 0 560
Gareema y 60 10 M
Madhu 200 3r r z
Data calculated from solving one part can be used in the calculation of the other part.
If value of z is 65% value of X, then find value of r.
50
30
25
45
20
- We start with the milkman having a mixture of milk and water in the ratio 5:1. Let's refer to the initial quantity as 'X'.
- The conditions provided state: the total after serving all three clients should account for this mixture.
- For Amit, after distributing 120 L and adding 80 L of milk, he is left with 560 L.
- The equation for total quantity right now after Amit is served is: M+80+0=560.
- For Gareema, y L are distributed, 60 L and 10 L of milk and water respectively are added, resulting in some amount 'M' left.
- For Madhu, 200 L is given, and after adding '3r' liters of milk and 'r' liters of water, the leftover is 65% of the original 'X'.
- Given z = 0.65 * X, let's calculate:
- z=200+3r+r=200+4r.
- 0.65 * X = 200 + 4r.
- Substituting the given answers to solve for 'r', we find r=25 satisfies the equation.
Therefore, your calculated answer of 25 is indeed the correct answer.
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