Explanation:

Let's break down the clues step by step:

- 10 people: Row 1 (A, B, C, D, E) facing south; Row 2 (F, G, H, I, J) facing north.

- B sits at the left end of Row 1 and has 11 chocolates, which is 9 more than the rightmost person in Row 1 (so rightmost has 2).

- D and C are not at the ends; D is to the right of C.

- E sits opposite J, who is second from one end. J has the highest (12) chocolates.

- H is second to the left of J, and faces the one with 6 chocolates.

- The third from the left end of Row 1 has a prime number of chocolates.

- E has more chocolates than I.

- A is diagonally opposite I, who has an even number.

- G has equal people left and right—so sits in the middle of Row 2.

- F has an odd number of chocolates.

- F + H’s chocolates is a perfect square, less than G’s chocolates.

Now, let's check who is second to the right of H in Row 2 (facing north):

- If H is second from left (because H sits second to the left of J, who is not at the corner), then possible arrangements:

- Row 2 (Left to right): F, H, G, J, I (since G must be in center; if J is second from right or left, best fit is here).

- So, H is second from left, G in the middle. Second to the right of H would be J.

Options:

- 1. F

- 2. I

- 3. G

- 4. J

- 5. None of the above

Correct answer:

Option 4 - J is correct. The person sitting second to the right of H is J.

- B at the left, E opposite J.

- D right of C, so order is B, C, D, A, E.

- G in center in Row 2.