If B works with 60 more than his minimin efficiency then find the ratio of total units of work by B ...........

Data Interpretation ( SBI PO) Data Table

Directions: Refer the table given below and answer the the following questions with the help of Actual work done by persons A, B and C with the maximum time required by each to complete the work. Data about three persons A, B and C is given in the table below:

Person Actual work done Maximum time(in hours)

A 50 units 10

B 60 units 12

C 15

If B works with 60% more than his minimin efficiency, then find the ratio of total units of work by B and total units of rest by B.

This questions was previously asked in

SBI PO Prelims (02 Jan, 2022)

View All SBIPO Previous Year Papers

0.5 : 0.3

2.1 : 1.2

4.3 : 2.5

1.7 : 5.2

None of the above

Explanation:

Let’s break this down, step by step:

- B’s actual work done is 60 units in a maximum of 12 hours. That means his minimum efficiency is 60/12 = 5 units/hour.

- If B works with 60% more than his minimum efficiency, his new efficiency becomes 5 + (60% of 5) = 5 + 3 = 8 units/hour.

- To do 60 units at 8 units/hour, B would need 60/8 = 7.5 hours of work.

- So, B's rest time = Maximum allowed time - time actually worked = 12 - 7.5 = 4.5 hours.

- Now, the question asks for the ratio of total units of work by B (60 units) to total units of rest by B (in units equivalent). Since B produces 8 units per hour now, in 4.5 hours of rest, the “lost” work is 8 × 4.5 = 36 units.

- Therefore, the ratio is 60 : 36, or simplified, 5 : 3 (or 0.5 : 0.3 if both sides are divided by 10).

Comparing this to the options:

Option 1: 0.5 : 0.3

Option 2: 2.1 : 1.2

Option 3: 4.3 : 2.5

Option 4: 1.7 : 5.2

Option 5: None of the above

So, the correct answer is Option 1: 0.5 : 0.3

That’s the logic—work out how much B actually did, what he could have done in the time he rested, then put those numbers together as a ratio. Done.