a b 102 104 107 113 128 173 Note calculate values of a and b then answer the questions those follow ...........

Quantitative Aptitude (SBI-PO) Number series

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a), (b), 102, 104, 107, 113, 128, 173

Note: calculate values of (a) and (b), then, answer the questions those follow:

Double the value of (a), let it be x. Then, find the difference between x and 4th term of series given

This questions was previously asked in

SBI PO Prelims (02 Jan, 2022)

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164

102

None of the above

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Explanation:

Correct option 2: 88
The series follows the following pattern:
102 + (1 x 2) = (102+2)=104
⇒ 104 + (1.5 x 2) = (104 + 3) = 107
107+ (2x 3) (107+6) = 113
113+ (2.5 x 6) = (113+15)=128
128+ (315) = (128 +45) = 173
According to that series, there is an increase of 0.5
So, At the place of (a) and (b) we have,
96+ (0.5 x 8) = (96+4)= 100
100+ (1 x 2)) = (100+ 2) = 102
The value of a = 96
The value of b = 100
So, The series are:
96+ (0.5 x 8) = (96+4)= 100
100+ (1 x 2)) = (100+2)=102
102 + (1 x 2) = (102 + 2) = 104
104 + (1.5 x 2) = (104 + 3) = 107 107+ (2x 3) = (107+6)=113 113+ (2.5 x 6) = (113 +15)= 128
128+ (315) = (128 +45) = 173
According to the question
Double the value of (a), let it be x
⇒ (96 × 2) = x
=192 = x
The 4th term of given series = 104
The difference x and 4th term of series = (192-104)
=88
-The required value le 88