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Directions: Study the following information carefully and answer the questions given below: In a hexagon arrangement, at each corner, a triangle is placed which is denoted by either two letters or two numbers. Below are given some of the conditions:
I. If the number is a perfect square then only that number is increased by 1.
II. If there is at least one vowel then change it to the preceding alphabet.
III. If both digits are odd then reduce those digits by 2.
IV. If any one of the consonants is smaller than N in alphabetical order then change it to the next alphabet.
Note: If no condition is applied then there will be no change. Apply the above-given conditions to find the output. More than one condition can be applicable. For example:
Input Output
Triangle 1 1, 4 2, 5
Triangle 2 o, k n, l
Triangle 3 6, 7 6, 7
Triangle 4 i, l h, m
Triangle 5 s, v s, v
Triangle 6 5, 5 3, 3
Input
Triangle 1 c, d
Triangle 2 u, b
Triangle 3 7, 7
Triangle 4 h, f
Triangle 5 w, q
Triangle 6 8, 3
What is the output of triangle 1?
b, e
d, a
b, a
d, e
c, d
Let’s walk through the logic, then check your answer.
Statements, in plain words:
- If you’ve got a perfect square number, add 1 to it.
- If either letter’s a vowel (a, e, i, o, u), swap it for the letter just before it in the alphabet.
- If both digits are odd, knock 2 off each.
- If any consonant is alphabetically *before* N, switch it to the next letter.
Input for Triangle 1:
What applies here?
- c and d, both consonants. Are any vowels involved? No.
- Are either c or d before N? Well, c is before N and so is d.
- That means: change to the next alphabet for each.
- c ? d, d ? e
So Triangle 1 output should be d, e.
Options:
Option 4: d, e
Here’s why each option either works or doesn’t:
- Option 1: b, e — b isn’t what you get from c.
- Option 2: d, a — d is right, a is not what you get from d.
- Option 3: b, a — both wrong outputs.
- Option 4: d, e — correct, as shown above!
- Option 5: c, d — no change at all. Rules say you’d have to bump each letter up by one.
So, you nailed it. The output for triangle 1 is d, e.
By: Parvesh Mehta ProfileResourcesReport error
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