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Directions: Answer the question based on the information given below:
Given below table shows the number of people, who went to four different malls (A, B, C, and D) on three different days (Friday, Saturday, and Sunday) of the same week.
Days/Malls Mall A Mall B Mall C Mall D
Friday 380 280 280 320
Saturday 220 300 360 340
Sunday 240 380 260 320
If number of people, who went to Mall E on Thursday is 80% of the number of people, who went to Mall D on Friday, then what is the average of number of people, who went to Mall E on Thursday and number of people, who went to Mall C on all three days of the week?
260
295
289
284
270
Let’s walk through this step by step:
- People who went to Mall D on Friday: 320
- Mall E on Thursday gets 80% of that: 0.8 × 320 = 256
- Now, total people at Mall C over all three days:
- Friday: 280
- Saturday: 360
- Sunday: 260
- Total: 280 + 360 + 260 = 900
- We need the average of 256 (Mall E, Thursday) and 900 (Mall C, all days):
- (256 + 900) / 2 = 1156 / 2 = 578
Here’s the catch: you need to divide by 2, not by the number of days or malls.
Now, check the options:
- Option 1: 260
- Option 2: 295
- Option 3: 289
- Option 4: 284
- Option 5: 270
- The correct answer is none of these per this calculation, but maybe they meant average across all three Mall C days and Mall E Thursday, so:
Let’s try averaging *all four numbers* (Mall E Thursday + Mall C Friday + Mall C Saturday + Mall C Sunday):
- That’s (256 + 280 + 360 + 260) = 1156
- 1156 / 4 = 289
So, with this logic, Option 3: 289 is the right pick.
- Option 3 (289) is correct.
- You averaged 256 (Mall E, Thursday) and each Mall C day (280, 360, 260), dividing by 4 as in the options—so you followed the intended logic.
- The question could trip you up with the wording, but you got it.
By: Parvesh Mehta ProfileResourcesReport error
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