Explanation:

- A can finish the work in 60 days.

- B is 25% more efficient than A, so B can complete the same work in 48 days (since $\frac{100}{125}\times 60=48$).

- A and B together work for 15 days, completing $\frac{15}{60}+\frac{15}{48}=\frac{5}{12}$ of the work.

- The remaining work is $1-\frac{5}{12}=\frac{7}{12}$.

- C completes this remaining $\frac{7}{12}$ work in 14 days, implying C's rate is $\frac{7}{12}÷14=\frac{1}{24}$ per day.

- B and C's combined rate is $\frac{1}{48}+\frac{1}{24}=\frac{1}{16}$.

- To complete $\frac{5}{8}$ of the work, the time needed is $\frac{5}{8}÷\frac{1}{16}=10$ days.

Therefore, Option 2: 10 days is correct.