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There is a 120 L mixture of vinegar and water. The ratio of vinegar to water is 7 : 5. A shopkeeper mixes a certain amount of water in order to make the ratio of vinegar to water 5 : 6. The new quantity of water is what percentage of the original quantity of water in the mixture?
180%
156%
145%
165%
168%
- Initially, there is a 120 L mixture with a vinegar to water ratio of 7:5. This implies:
- Vinegar = (7/12) × 120 = 70 L
- Water = (5/12) × 120 = 50 L
- A certain amount of water is added, making the vinegar to water ratio 5:6:
- Vinegar remains 70 L.
- Let the new water quantity be W. Therefore, \(70/W = 5/6\).
- Solving gives W = 84 L.
- The new water quantity is 84 L. The percentage of new water relative to original water is:
- \((84/50) × 100 = 168%\).
- Correct answer: \(\large{\color{green}\checkmark}\) Option 5: 168%
By: Parvesh Mehta ProfileResourcesReport error
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