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Sanju, Suraj and Sanjay can complete a work in 12 days, 16 days and 24 days respectively. In how many days will the three of them to do the same work together?
16/3 days
58/9 days
6 days
8 days
None of these
- Determine individual work rates:
- Sanju completes the work in 12 days, so his work rate is \( \frac{1}{12} \) work/day.
- Suraj completes the work in 16 days, so his work rate is \( \frac{1}{16} \) work/day.
- Sanjay completes the work in 24 days, so his work rate is \( \frac{1}{24} \) work/day.
- Combine their work rates:
- Combined rate = \( \frac{1}{12} + \frac{1}{16} + \frac{1}{24} \).
- Calculate the combined rate:
- Find a common denominator (48) and add:
$$ \frac{4}{48} + \frac{3}{48} + \frac{2}{48} = \frac{9}{48} = \frac{3}{16} $$.
- Find the total time together:
- Total time = \( \frac{1}{\frac{3}{16}} = \frac{16}{3} \) days.
- Correct Option:
- Option:1, \( \frac{16}{3} \) days
By: Parvesh Mehta ProfileResourcesReport error
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