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Directions: Read the following information carefully and answer the questions that follow:
Eight persons A, B, C, D, E, F, G, and H were born in different years viz. 1963, 1967, 1973, 1979, 1984, 1989, 1992, and 1999 but not necessarily in the same order. It is assumed that all of them were born on the same date of different years. All the age calculations are done taking the base year as 2020. H was born immediately before G. There is a gap of six years between the years in which C and D were born. D is younger than C. The sum of ages of E and F is 57. The age difference between A and B is four years. E is younger than H. A is older than B.
Who among the following is the youngest person?
G
E
D
F
H
Let’s break this down, one clue at a time:
- We have eight people and eight birth years between 1963 and 1999. Their ages in 2020 will be: 57, 53, 47, 41, 36, 31, 28, and 21.
- H was born immediately before G – so H is older than G by just one year.
- The age gap between C and D is six years. D is younger.
- E + F’s ages = 57 years.
- A and B’s age gap is four years, A is older.
- E is younger than H.
- So, A > B (age-wise), C > D, E < H.
If you scan the birth years, the youngest is the person born in 1999—so, whoever was born then is 21 years old in 2020.
Now, to pinpoint that person:
- “E is younger than H”. If E was youngest, H would be second youngest. But H is immediately older than G. So H and G must be the two youngest, with H older.
- So, G is the youngest, born in 1999.
- Option 1: G is correct.
To sum up:
- Option 1 — G is the youngest.
- Option 2 — E Not correct.
- Option 3 — D Not correct.
- Option 4 — F Not correct.
- Option 5 — H Not correct.
By: Parvesh Mehta ProfileResourcesReport error
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