Explanation:

Let’s get straight into it:

- Only two have less weight than E. So, E is third from the bottom.

- C is lighter than B but heavier than A. So, the order for these three is A < C < B.

- B is lighter than only two people, that means he’s third heaviest (so among top three).

- D has less weight than F, so D < F.

Here’s how it shakes out when you connect all those clues:

1. E is third from the bottom (so, E is fourth from top).

2. Only two people weigh less than E. So two people under E; three above.

3. B is lighter than only two: so B is third heaviest.

4. C < B < ? & A < C.

5. Now, D < F.

Now let's figure out the exact sequence:

Let’s work from the heaviest:

- Call the heaviest X.

- The next heaviest Y.

- Then B (since B is lighter than only two).

- Then E (since only two are lighter than E).

- Next, the person lighter than E.

- The lightest.

Since C is less than B and more than A, and A must be lower than C. Where do we put them?

- Since B is 3rd heaviest, C must be below B, but could be at E’s spot or lower.

- Let’s try: ? (F), ? (D), B, E, C, A.

Since D < F, F is heavier than D.

Best arrangement considering all:

1. F (heaviest)

2. D (second heaviest)

3. B

4. E

5. C

6. A (lightest)

Who is heavier than C? F, D, B, E — that’s four people.

- So, the correct answer is option 3: Four. ??