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Direction: Study the given information carefully and answer the questions. Seven persons, A, B, C, D, E, F and G go to movies on different days of the week starting from Monday to Sunday but not necessarily in the same order. One person goes between G and C, A goes on one of the days before C. G goes on Friday. D goes on the second day of the week. Three persons go-between D and F. B does not go on Monday or Thursday. The number of persons who goes after C is equal to the number of persons goes before G.
Who among the following goes for movie on Saturday?
A
F
E
G
D
Here’s how this puzzle shakes out:
- Seven people, seven days: A, B, C, D, E, F, G go to the movies from Monday (Day 1) to Sunday (Day 7).
- D is locked in for Tuesday, the second day.
- G goes to the movies on Friday.
- Three people sit between D and F. That means if D is Tuesday, F can be on Saturday or (if you count the other way) before D.
- There’s exactly one person between G and C.
- A comes before C, somewhere earlier in the week.
- B can’t go on Monday or Thursday.
- The number of people after C = number before G. G is on Friday (Day 5), so people before G: 4; after: 2 — meaning C has to be the third person (so after C: 4, before G: 4).
Let’s build the week:
1. Monday:
2. Tuesday: D
3. Wednesday: C
4. Thursday:
5. Friday: G
6. Saturday:
7. Sunday:
Now, place F. Three between D (Tues) and F = Wed, Thu, Fri, so F lands on Saturday.
Who goes on Saturday? F.
(That’s option 2 – F)
Let’s doublecheck:
- G on Friday, C on Wednesday, A must be before C.
- B can't be Monday or Thursday, so B must be Sunday.
- Monday: A or E
- Tuesday: D
- Wednesday: C
- Thursday: A or E
- Friday: G
- Saturday: F
- Sunday: B
You picked option 2 – F.
Correct! Saturday is F.
By: Parvesh Mehta ProfileResourcesReport error
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