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The square of the difference between two given natural numbers is 324, while the product of these two given numbers is 144. Find the positive difference between the squares of these two given numbers.
630
540
450
360
Let's break down the problem:
- Let the two natural numbers be x and y, with x > y.
- The square of their difference: (x - y)² = 324 ? x - y = 18 (since 18² = 324; we take positive root for natural numbers).
- Their product: x·y = 144.
- We are asked for the positive difference between the squares: |x² - y²|.
Calculation:
- x² - y² = (x - y)(x + y) = 18·(x + y).
- From earlier: x·y = 144 and x - y = 18.
- So, x and y are roots of t² - (x + y)t + x·y = 0.
- Let S = x + y.
- x and y: roots of t² - St + 144 = 0, with x - y = 18.
- System:
- x + y = S
- x - y = 18
- Solving:
- x = (S + 18)/2
- y = (S - 18)/2
- x·y = 144 ? [(S + 18)/2]·[(S - 18)/2] = 144 ? (S² - 324)/4 = 144 ? S² - 324 = 576 ? S² = 900 ? S = 30
- So, x + y = 30.
- Therefore, x² - y² = 18 × 30 = 540
Let’s match with options:
- Option 1: 630 ?
- Option 2: 540
- Option 3: 450 ?
- Option 4: 360 ?
Key Points:
- The correct answer is Option 2: 540.
- The method: Find x - y, use product xy, solve for x + y, then find the difference of their squares.
- Other options don’t match the computed result.
By: Parvesh Mehta ProfileResourcesReport error
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