send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A 15 cm long perpendicular is drawn from the centre of a circle to its 40 cm long chord. Find the radius of the circle.
25 cm
27 cm
22 cm
20 cm
- A perpendicular from the center of a circle to a chord bisects the chord.
- Chord length = 40 cm, so each half is 20 cm.
- A right triangle is formed with the radius as the hypotenuse, half the chord as one leg, and the perpendicular as the other leg.
- Use the Pythagorean theorem: \((\text{radius})^2 = (\text{perpendicular})^2 + (\text{half of chord})^2\).
- Substitute values: \((\text{radius})^2 = 15^2 + 20^2\).
- Calculate: \((\text{radius})^2 = 225 + 400 = 625\).
- Radius = \(\sqrt{625} = 25\) cm.
- Option 1: 25 cm is correct.
.
By: Parvesh Mehta ProfileResourcesReport error
Access to prime resources
New Courses