An 18 m deep well with diameter 7 m is dug and the earth from digging is spread evenly to form a pla...........

Quantitative Aptitude (CPO) Mensuration 2D

An 18 m deep well with diameter 7 m is dug and the earth from digging is spread evenly to form a platform 18 m × 14 m. The height

of the platform is:

This questions was previously asked in

SSC CPO 15th-March-2019-Shift-2

2.6 m

3.05 m

2.75 m

3.2 m

- First, calculate the volume of the earth dug from the well.

- The well is cylindrical. Use the formula for the volume of a cylinder: \(V = \pi r^2 h\).

- The radius \(r\) is half the diameter, so \(r = 3.5\) m.

- The depth \(h\) is 18 m.

- Volume \(V = \pi \times (3.5)^2 \times 18\).

- Calculate the volume of the platform created from the earth from the well.

- The platform is a rectangular prism. Use the formula: Volume = length \(\times\) width \(\times\) height.

- Length = 18 m, width = 14 m, and we need to find the height \(h\).

- Set the volume of the earth from the well equal to the volume of the platform.

- \(\pi \times (3.5)^2 \times 18 = 18 \times 14 \times h\).

- Solve for \(h\) to find the height of the platform.

- On solving, \(h ˜ 2.75\) m.

- Correct Answer: Option 3 - 2.75 m.

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