send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
Two numbers are in the ratio 4 : 9. If both the numbers are increased by 12, the ratio becomes 11 :21. The sum of the original
numbers is:
128
64
52
104
- Let's denote the two numbers as 4x and 9x, given their ratio is 4:9.
- When both numbers are increased by 12, they become 4x + 12 and 9x + 12.
- The new ratio is given as 11:21.
- Set up the equation: (4x + 12)/(9x + 12) = 11/21.
- Cross-multiply to get: 21(4x + 12) = 11(9x + 12).
- Simplify the equation: 84x + 252 = 99x + 132.
- Rearrange to get: 252 - 132 = 99x - 84x, resulting in 120 = 15x.
- Solve for x: x = 8.
- Original numbers are 32 and 72.
- Their sum = 32 + 72 = 104.
The sum of the original numbers is 104.
By: santosh ProfileResourcesReport error
Access to prime resources
New Courses