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The least number that should be added to 10000 so that it is exactly divisible by 327 is:
327
237
137
190
327 is a multiple of 3. So, a number should be added to 10000 which will make it divisible by 3. And 327 is also a multiple of 109. So, To make 10000 completely divisible by 327, a number should be added to that number which would be divisible by 109 also. So, (10000 + 137) = 10137 is divisible by 3 as well as 109. So,Option C is correct.
By: santosh ProfileResourcesReport error
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