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Three pipes X. Y and Z discharge three different chemicals A. B and C in a tank. The pipes can fill the tank in 20. 25 and 40 minutes
respectively. What will be the proportion of chemical B in the tank, if all the pipes are open for 10 minutes?
In 1 minute A,B and C together can fill the tank is = (1/20) + (1/25) + (1/40) = (10 + 8 + 5)/200 = 23/200. So,in 10 minutes they can fill (230/200). B can fill in 10 minutes is = 10/25. So, proportion in B will be = (200/230) × (10/25). = 8/23. So, C is correct choice.
By: santosh ProfileResourcesReport error
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