A goes to a mall from his house on a cycle at 8 km h and comes back to his house on a cycle at 6 km ...........

Quantitative Aptitude (CPO) Time & distance

A goes to a mall from his house on a cycle at 8 km/h and comes back to his house on a cycle at 6 km/h. If he takes 1 hour 10 minutes

in all, what is the distance between his house and the mall?

This questions was previously asked in

SSC CPO 14th-March-2019-Shift-1

5 km

6 km

4 km

8 km

- Given Speed to the Mall: 8 km/h

- Given Speed Returning: 6 km/h

- Total Time Taken: 1 hour and 10 minutes (which is 1 + 10/60 = 1.1667 hours)

- Let Distance to the Mall Be: D km

- Time to Mall: D/8

- Time Returning: D/6

- Total Time Equation: D/8 + D/6 = 1.1667

- Finding Common Denominator:

- (3D + 4D) / 24 = 1.1667

- 7D = 1.1667 * 24

- 7D = 28

- D = 4

- Correct Option: Option 3, 4 km

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