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The sides of a triangular park are in the ratio of 12 : 17 : 25 and its perimeter is 1080 m. The area (in hectares) of the park is .............
3.6
4.2
4.5
4.8
- The sides of the triangular park are in the ratio 12:17:25.
- The perimeter of the park is given as 1080 meters.
- Let the sides be 12x, 17x, and 25x. The sum is 1080 meters:
$$
12x + 17x + 25x = 1080 \rightarrow 54x = 1080 \rightarrow x = 20
- Thus, the sides are 240 m, 340 m, and 500 m.
- Use Heron's formula to find the area. First, calculate the semi-perimeter:
s = \frac{1080}{2} = 540
- Then, apply Heron's formula:
\text{Area} = \sqrt{s(s-240)(s-340)(s-500)}
\text{Area} = \sqrt{540 \times 300 \times 200 \times 40}
\text{Area} = \sqrt{1296000000} = 36000 \text{ square meters}
- Convert square meters to hectares (1 hectare = 10,000 square meters):
\text{Area in hectares} = \frac{36000}{10000} = 3.6 \, \text{hectares}
- Option 1: 3.6 is the correct answer.
.
By: santosh ProfileResourcesReport error
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