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The average of twelve numbers is 58. The average of the first five numbers is 56 and the average of the next four numbers is 60. The
10th number is 4 more than the 11th number and the 11th number is one less than the 12th number. What is the average of the 10th
and 12th numbers?
58.5
59.5
59
58
Certainly! Let me explain step by step:
- The total sum of all twelve numbers is \(12 \times 58 = 696\).
- The sum of the first five numbers is \(5 \times 56 = 280\).
- The sum of the next four numbers is \(4 \times 60 = 240\).
- The sum of the remaining three numbers (10th, 11th, and 12th) is \(696 - 280 - 240 = 176\).
- Let's denote the 11th number as \(x\).
- The 10th number is \(x + 4\), and the 12th number is \(x + 1\).
- So, \(x + 4 + x + x + 1 = 176\).
- This equation simplifies to \(3x + 5 = 176\).
- Solving for \(x\), we get \(3x = 171\), therefore \(x = 57\).
- The 10th number \(= x + 4 = 61\).
- The 12th number \(= x + 1 = 58\).
- The average of the 10th and 12th numbers \((61 + 58) / 2 = 59.5\).
- Option 2: 59.5
By: santosh ProfileResourcesReport error
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