Two chords AB and CD of a circle intersect each other at P internally If AP 3 5 cm PC 5 cm and DP 7 ...........

Quantitative Aptitude (CPO) Geometry

Two chords AB and CD of a circle intersect each other at P internally. If AP = 3.5 cm, PC = 5 cm, and DP = 7 cm, then what is the

measure of PB?

This questions was previously asked in

SSC CPO 13th Dec 2019 Shift-1

8 cm

12 cm

10 cm

10.5 cm

- According to the Intersecting Chords Theorem, the products of the lengths of the segments of each chord are equal.

- For chords AB and CD intersecting at P:

- AP × PB = CP × PD.

- Given:

- AP = 3.5 cm

- PC = 5 cm

- DP = 7 cm

- Using the theorem:

- 3.5 × PB = 5 × 7

- 3.5 × PB = 35

- PB = 35 / 3.5

- PB = 10 cm

- Therefore, the correct measure of PB is 10 cm.

Option:3 - 10 cm

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