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The efficiencies of A. B and C are in the ratio 5 : 6 : 8. Working together. they can complete a piece of work in 120 hour's. In how many
hours will, B alone be able to complete 40% of that work?
152
182.4
167.2
114
- The efficiencies of A, B, and C are in the ratio 5:6:8.
- Together, A, B, and C can finish the work in 120 hours.
- Calculate the total work: The combined efficiency ratio is 5+6+8 = 19.
- Thus, total work = 19 * 120 = 2280 units.
- B's efficiency is part of the ratio, which is 6.
- So, B can do 6 units of work per hour.
- Calculate 40% of the work: 40% of 2280 = 912 units.
- Determine time for B to complete 912 units: 912 / 6 = 152 hours.
- Correct Answer: Option 1: 152
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