Explanation:

- The problem defines two scenario speeds for a train: 36 km/h and 45 km/h.

- At 36 km/h, the train arrives 15 minutes late.

- At 45 km/h, the train arrives 4 minutes late.

- The difference in lateness is 11 minutes (15 - 4).

- Calculate the time it would have taken to cover the journey at these speeds without any non-lateness.

- Correct time calculation: Let the time taken without delays be x minutes.

- For 36 km/h: \( \frac{x+15}{60} \times 36 \)

- For 45 km/h: \( \frac{x+4}{60} \times 45 \)

- The distances are the same, set equations equal:

\(\frac{x + 15}{60} \times 36 = \frac{x + 4}{60} \times 45\)

- Simplify and solve the equation for x.

- Correct Answer: 40 minutes

- This makes the correct journey time without any delays as 40 minutes.

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