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A conical vessel whose internal base radiusis 18 cm and height 60 cm is full of a liquid. The entire liquid of the vessel is emptied into
a cylindrical vessel with internal radius 15 cm. The height (in cm) to which theliquid rises in the cylindrical vessel is:
28.8 cm
30.2 cm
27 cm
24 cm
To solve the problem, we need to follow these steps:
- Calculate the volume of the conical vessel:
- Formula: \( V = \frac{1}{3} \pi r^2 h \)
- Here, \( r = 18 \) cm and \( h = 60 \) cm.
- Volume = \(\frac{1}{3} \times \pi \times 18^2 \times 60\).
- Calculate the volume of liquid displaced in the cylindrical vessel:
- Let the height of the liquid in the cylindrical vessel be \(H\).
- Formula: \( V = \pi r^2 H \)
- Here, \( r = 15 \) cm.
- Equate the volumes to find \(H\).
- Use the volume relation:
- \(\frac{1}{3} \times \pi \times 18^2 \times 60 = \pi \times 15^2 \times H\).
- Simplifying gives \(H = 28.8\) cm.
- Conclusion:
- Option 1: 28.8 cm is the correct answer.
By: santosh ProfileResourcesReport error
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