Pipes A and B together can fill a tank in 16 hours where as pipe C alone can empty the full tank in ...........

Quantitative Aptitude (CPO) Pipes&cistern

Pipes A and B together can fill a tank in 16 hours, where as pipe C alone can empty the full tank in 24 hours. A and B were opened

together for 10 hours and then closed. Pipe C was then opened. The tank will now be emptied by C in:

This questions was previously asked in

SSC CPO 12th Dec 2019 Shift-1

10 hours

12 hours

15 hours

18 hours

Let's break down the problem step by step:

- Pipes A and B together fill the tank in 16 hours. So, their combined rate is 1/16 of the tank per hour.

- In 10 hours, A and B fill: 10 × (1/16) = 10/16 = 5/8 of the tank.

- Tank filled after 10 hours = 5/8 full.

- Pipe C empties the whole tank in 24 hours, so its rate is 1/24 per hour.

- Amount of tank left to be emptied = 5/8 full, so the emptying required = 5/8 of the tank.

- Time taken by C to empty = (5/8) ÷ (1/24) = (5/8) × 24 = 15 hours.

So the correct option is:

- 10 hours

- 12 hours

- 15 hours (Correct Answer)

- 18 hours

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