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After starting from her house, Sameera walked a few metres towards the East. From there. she took a right turn and walked 100 m,
and then took a left turn and walked 30 m. Finally, she took a left turn again and walked 40 m to reach the market. If the air distance
between her house and the market is 100 111. how far did Sameera walk towards the East initially from her house?
30 m
80 m
60 m
50 m
- Sameera starts at her house and walks some distance east.
- She then turns right (south) and walks 100 meters.
- She takes a left turn (east) and walks another 30 meters.
- Finally, she takes a left turn again (north) and walks 40 meters to reach the market.
- The air distance (straight line) from her house to the market is 100 meters.
To find out how far she initially walked east:
- Since she ends up north from her original east-west line, we can create a right triangle.
- The northward distance cancels out, which simplifies calculations.
For horizontal distance:
- Total eastward distance: initial unknown distance + 30 meters.
- Calculate hypotenuse using the right triangle formula: \( a^2 + b^2 = c^2 \).
- \( 100^2 = (40 + 30 + x)^2 + 0^2 = 100^2 \).
Finding \( x \):
- Solve: \( 100^2 = (70 + x)^2 \).
Thus, the correct initial distance east would be:
- 50 m $$ \text{(Because } 60 + 40 = 100 \text{ and } 80 + 20 = 100)$$
- Correct Answer: 50 m
By: santosh ProfileResourcesReport error
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