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Three of the following four letter-clusters are alike in a certain way and one is different. Find the odd one out.
MKOH
CLEH
TRVN
PYRU
- Let's break down the pattern in each letter-cluster:
- MKOH: Replace each letter with its position in the alphabet: M(13), K(11), O(15), H(8).
- CLEH: Positions are C(3), L(12), E(5), H(8).
- TRVN: Positions are T(20), R(18), V(22), N(14).
- PYRU: Positions are P(16), Y(25), R(18), U(21).
- Pattern Analysis:
- Observe each cluster: MKOH, CLEH, TRVN, PYRU
- The last letter's position is increasing by different inter-changing step-size.
- Odd one out:
- All letter clusters have alternating increases in numbers except in MKOH, which breaks the step-size pattern.
- So, MKOH is structured differently.
- Answer:
- MKOH is the odd one.
- Option 1: MKOH is the correct answer.
By: santosh ProfileResourcesReport error
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