The total numbers of males and females in a town is 70 000 If the numberof males is increased by 6 a...........

Quantitative Aptitude (CPO) Percentage

The total numbers of males and females in a town is 70,000. If the numberof males is increased by 6% and that of the females is

increased by 4%, then the total numbers of males and females in the town would become 73520. Whatis the difference between the

numberof males and females in the town, in the beginning?

This questions was previously asked in

SSC CPO 11th Dec 2019 Shift-2

1500

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2000

1400

- Let's denote the number of males as M and females as F.

- We have the equation: M + F = 70,000.

- When males increase by 6%, we have 1.06M.

- When females increase by 4%, we have 1.04F.

- The total new population becomes 1.06M + 1.04F = 73,520.

To find the difference:

- From M + F = 70,000, we can express F as F = 70,000 - M.

- Substitute F in the new population equation:

- 1.06M + 1.04(70,000 - M) = 73,520.

- 1.06M + 72,800 - 1.04M = 73,520.

- 0.02M = 720.

- M = 36,000.

- Then, F = 70,000 - 36,000 = 34,000.

- So, the difference is |36,000 - 34,000| = 2,000.

- Option:3 - 2000 is the correct answer.

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