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A solid metallic sphere of radius 6.3 cm is melted and recast into a right circular cone of height 25.2 cm. What is the ratio of the
diameter of the base to the height of the cone?
2 : 1
3 : 2
1 : 2
2 : 3
- The original sphere has a radius of 6.3 cm.
- Volume of sphere: \(V = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (6.3)^3\).
- The sphere is melted to form a cone.
- Volume of cone: \(V = \frac{1}{3} \pi r^2 h\), where \(h = 25.2\) cm is given.
- Equate volumes to find the cone's base radius.
- Calculate: \(\frac{4}{3} \pi (6.3)^3 = \frac{1}{3} \pi r^2 (25.2)\).
- Calculate the base radius \(r\) and then the diameter \(2r\).
- Ratio of diameter to height:
$$
\left(\frac{2r}{25.2}\right)
- After solving, you find the ratio \(\frac{1}{2}\).
Correct Answer: Option: 3 (1 : 2)
By: santosh ProfileResourcesReport error
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