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From the top of a house A in a street, the angles of elevation and depression of the top and foot of another house B on the opposite
side of the street are 60o and 45o respectively. If the height of house A is 36 m, then what is the height of house
B? (Your answer should be nearest to an Integer.)
91 m
93 m
94 m
98 m
Let’s break this down:
-
From the top of House A (36 m high), you look at House B across the street.
The angle up (elevation) to B’s top: 60°. The angle down (depression) to B’s base: 45°.
Imagine a horizontal line from A’s top—call street width “x” and height of B “h”.
From A’s top to B’s foot: 45° depression, so drop of 36 m over distance x ? x = 36 m (tan 45° = 1).
From A’s top to B’s top: 60° elevation, rise of (h - 36) over same distance x ? tan 60° = (h-36)/36.
So, v3 = (h-36)/36 ? h-36 = 36v3 ? h = 36(1 + v3) ˜ 36 × 2.732 = 98.35 m.
Option 4 (98 m) is correct.
All the pieces fit.
By: santosh ProfileResourcesReport error
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