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When 2388, 4309 and 8151 are divided by a certain 3-digit number, the remainder in each case is the same. The remainder is:
39
23
19
15
Correct option 4: 15 As we know, 4309-2388 = 1921 8151-4309 = 3842 8151-2388 = 5763 HCF of 1921, 3842 and 5763 is 1921. As we know, 1921 = 17 x 113 So, the three-digit number is 113. When we divide 2388, 4309 and 8151 by 113 we find remainder 15 in each case.
By: santosh ProfileResourcesReport error
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