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Pipes A, B and C can fill a tank in 10, 15 and 30 hours, respectively. D is an emptying pipe which alone can empty the full tank in x
hours. A, B and C are opened together for 3 hours and then closed. Now D is opened which alone empties the tank in 30 hours. What
is the value of x ?
40
50
60
45
Let's solve the problem step by step:
- Pipes A, B, and C fill the tank in 10, 15, and 30 hours, so:
- A's rate = 1/10 per hour
- B's rate = 1/15 per hour
- C's rate = 1/30 per hour
- Combined rate of A, B, and C:
- 1/10 + 1/15 + 1/30 = (3 + 2 + 1)/30 = 6/30 = 1/5 of the tank per hour
- In 3 hours, together they fill:
- 3 × (1/5) = 3/5 of the tank
- Then D is opened, and it empties the tank in 30 hours now.
- D empties (3/5) tank in 30 hours.
- So, D's rate = (3/5)/30 = 1/50 per hour
- But D alone takes x hours to empty full tank.
- So, D's original rate = 1/x per hour
- Equating:
- 1/x = 1/50 ? x = 50
Options:
- Option 1: 40 (incorrect)
- Option 2: 50 (correct)
- Option 3: 60 (incorrect)
- Option 4: 45 (incorrect)
- Correct option is Option 2: 50
By: santosh ProfileResourcesReport error
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