If 60 of x mdash y 45 x y and y k ofx then 21 of k is equal to ........

Quantitative Aptitude (CPO) Percentage

If 60% of (x — y) =45% (x + y) and y = k% ofx, then 21% of k is equal to

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SSC CPO 9th Dec 2019 Shift-2

Sure, let’s solve this step by step:

- You are given the equation: 60% of (x — y) = 45% of (x + y).

- Simplified, it becomes: 0.6(x - y) = 0.45(x + y).

- Expand both sides: 0.6x - 0.6y = 0.45x + 0.45y.

- Rearrange terms: 0.6x - 0.45x = 0.6y + 0.45y.

- Simplify: 0.15x = 1.05y.

- You are also given: y = k% of x, which means y = (k/100)x.

- Substitute y in the equation: 0.15x = 1.05(k/100)x.

- Cancel x from both sides and solve for k: 0.15 = 1.05k/100.

- This gives: k = 14.2857 (approximately).

- You need 21% of k, calculated as: 21% of 14.2857 = 3 (approximately).

Thus, the correct option is Option 3: 3.

- Your option is indeed correct.

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