send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
boys from school A and 6 boysfrom school B together can set up an exhibition in 5 days, which 5 boys from school A and 10 boys
from school C together can do in 4 days or 3 boys from school B and 4 boysfrom school C together can do in 10 days. Then how
manyboys from schoolA can set up the exhibition in one day?
80
40
60
20
- Let's define the rates: let A be the rate of one boy from School A, B the rate for School B, and C for School C.
- First statement: 9A + 6B = 1/5 (since they complete it in 5 days).
- Second statement: 5A + 10C = 1/4.
- Third statement: 3B + 4C = 1/10.
- Solve the system of equations to find A.
Using the equations:
- From third statement: 3B + 4C = 1/10.
- From first statement: 9A + 6B = 1/5.
- From second statement: 5A + 10C = 1/4.
After calculations, you'll find:
- One boy from School A (checking math) can do the work in 20 days.
- Therefore, the entire exhibition can be set up by 80 such boys in one day.
The correct answer is:
.
Report error
Access to prime resources