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Which is the largest six digit number, which when divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26
respectively.
999956
999960
999964
999982
The LCM of 12, 15 20,24, 30 = 120 the greatest of 6 digit = 999999 Dividing 999999 by 120 we get 39 as the remainder Hence the 6 digit number divisible by 120 is (999999-39) = 999960 Since 12-8=4 , 15-11 = 4, 20-16=4, 24-20= 4, 30-26 = 4 then reminder is each case is =4 less then the divior Hence Requried number 999960-4 = 999956
By: santosh ProfileResourcesReport error
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