Five men and 2 women can do a piece of work in 9 days whereas 11 men and 5 women can do the same wor...........

Quantitative Aptitude (MTS) Time and work

Five men and 2 women can do a piece of work in 9 days, whereas 11 men and 5 women can do the same work in 4 days. To

complete the same work in 6 days, the number of women required is:

This questions was previously asked in

SSC MTS 27th October 2021 Shift-2

- Let's denote the work done by one man in one day as M and by one woman in one day as W.

- The equation from the first scenario is: \(5M + 2W = \frac{1}{9}\) of the work.

- The equation from the second scenario is: \(11M + 5W = \frac{1}{4}\) of the work.

- Solving these equations gives the rates for M and W.

- For completion in 6 days, let the number of women required be X with 8 men, so \(8M + XW = \frac{1}{6}\) of the work.

- Substituting values from M and W, solve for X.

?? Option:2 - 18 is the correct answer according to these calculations.

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