Three jugs of equal capacity are filled with mixtures of milk and water in the proportions 3 1 7 1 a...........

Quantitative Aptitude (MTS) Mixture and Alligation

Three jugs of equal capacity are filled with mixtures of milk and water in the proportions 3 : 1, 7 : 1 and 11 : 5. The three jugs

are emptied into a single container. What will be the ratio of water to milk in the said container?

This questions was previously asked in

SSC MTS 18th October 2021 Shift-3

14: 45

11: 37

12: 41

15: 49

- We have three jugs with milk to water ratios of 3:1, 7:1, and 11:5.

- First jug: 3 parts milk, 1 part water; thus total parts = 4.

- Second jug: 7 parts milk, 1 part water; thus total parts = 8.

- Third jug: 11 parts milk, 5 parts water; thus total parts = 16.

- Assume each jug has 1 unit capacity.

Calculating total milk and water:

- First jug: 3/4 milk, 1/4 water.

- Second jug: 7/8 milk, 1/8 water.

- Third jug: 11/16 milk, 5/16 water.

Total milk = (3/4 + 7/8 + 11/16) = 37/16

Total water = (1/4 + 1/8 + 5/16) = 11/16

- Ratio of water to milk = (11/16) : (37/16) = 11:37

- Option: 2, 11:37

Submit Error