Four solid cubes each of volume 1728 cm3 are kept in two rows having two cubes in each row They form...........

Quantitative Aptitude (MTS) Mensuration 3D

Four solid cubes, each of volume 1728 cm³ , are kept in two rows having two cubes in each row. They form a rectangular solid

with square base. The total surface area (in cm² ) of the resulting solid is:

This questions was previously asked in

SSC MTS 18th October 2021 Shift-2

1440

2304

576

1152

- Each cube has a volume of 1728 cm³. Therefore, the side length of each cube is the cube root of 1728, which is 12 cm.

- The four cubes are arranged in a rectangular solid with a square base, composed of two cubes in one row and another two directly behind them.

- The base of the resulting solid is 24 cm x 24 cm since two cubes are placed side by side.

- The height of the resulting solid is 12 cm because only one cube is stacked in the vertical direction.

- The surface area of the solid can be calculated by the formula: Surface Area = 2(lh + lw + hw). Here, l = 24 cm, w = 24 cm, and h = 12 cm.

- The calculations give: Surface Area = 2(24*12 + 24*24 + 12*24) = 2304 cm².

The correct answer is: Option 2 - 2304

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