Jack takes thrice as much time as Peter and twice as much as Justin to finish a work working togethe...........

Quantitative Aptitude (MTS) Time and work

Jack takes thrice as much time as Peter and twice as much as Justin to finish a work; working together they can finish the

work in 15 days. The time (in days) Justin will take to finish the work alone is:

This questions was previously asked in

SSC MTS 18th October 2021 Shift-2

Let’s break down the statements and options:

- Let Peter take x days to finish the work.

- Jack takes 3x days (thrice Peter’s time).

- Justin takes (3x/2) days (since Jack takes twice as much as Justin ? Jack = 2×Justin).

- Work done per day: Peter = 1/x, Jack = 1/3x, Justin = 2/3x.

- Together: (1/x) + (1/3x) + (2/3x) = 1/15

- Combine: (1 + 1/3 + 2/3) / x = 1/15 ? (2)/x = 1/15 ? x = 30

- Justin’s time: (3x/2) = 45 days.

Let's look at the options:

1. 60 (Incorrect)

2. 90 (Incorrect)

3. 75 (Incorrect)

4. 45 (Correct)

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