Sita and Geeta start at the same time to ride from place A to place B which is 90 km away from A Sit...........

Quantitative Aptitude (MTS) Time & distance

Sita and Geeta start at the same time to ride from place A to place B, which is 90 km away from A. Sita travels 3 km per hours

slower than Geeta. Geeta reaches place B and at once turn back meeting Sita 15 km from B. Sita's speed (in km/h) is:

This questions was previously asked in

SSC MTS 13th October 2021 Shift-1

10.5

7.5

- Let Sita's speed be \( x \) km/h.

- Therefore, Geeta's speed is \( x + 3 \) km/h since she is faster by 3 km/h.

- Geeta travels 90 km to B and then 15 km back towards A, covering a total distance of 105 km.

- Total time taken by Geeta for this journey is \( \frac{105}{x+3} \) hours.

- During the same time, Sita travels 75 km (from A to 15 km short of B).

- The time Sita travels is \( \frac{75}{x} \) hours.

- Since both times are equal, \(\frac{105}{x+3} = \frac{75}{x}\).

- Solving this equation gives \( x = 7.5 \).

- Thus, Sita's speed is 7.5 km/h.

- ?? Correct answer: Option 4, 7.5 km/h

Submit Error