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A boy walked along two adjacent sides of a rectangular field. If he had walked along the diagonal,then he would have saved a
distance equal to one-fourth of the larger side. The ratio of the larger to the smaller side is:
7:24
11:18
24:7
18:11
- Let's define the sides of the rectangle as \(a\) (smaller side) and \(b\) (larger side).
- The distance walked along two sides is \(a + b\).
- The diagonal distance using the Pythagorean theorem is \(\sqrt{a^2 + b^2}\).
- It's given that by walking diagonally, a distance equal to \(\frac{1}{4}\) of the larger side \(b\) would be saved.
- So, \(a + b - \sqrt{a^2 + b^2} = \frac{b}{4}\).
- Rearranging, \(\sqrt{a^2 + b^2} = a + \frac{3b}{4}\).
To find the ratio of \(b\) to \(a\):
1. Substitute the given options into the equation \(\sqrt{a^2 + b^2} = a + \frac{3b}{4}\) to find which one satisfies the equality.
2. For option 1 (\(\frac{b}{a} = \frac{7}{24}\)), it doesn't satisfy.
3. For option 2 (\(\frac{b}{a} = \frac{11}{18}\)), it doesn't satisfy.
4. For option 3 (\( \frac{b}{a} = \frac{24}{7} \)), it satisfies the equation.
5. For option 4 (\(\frac{b}{a} = \frac{18}{11}\)), it doesn't satisfy.
By: santosh ProfileResourcesReport error
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