Multiple Choice Questions

Vaishnav left from place A at 11 a m for place B and suman left from place B at 2 p m for place A Th...........

Quantitative Aptitude (MTS) Time & distance

Vaishnav left from place A at 11 a.m for place B, and suman left from place B at 2 p.m for place A.The distance between them is

516 km. If Vaishnav's speed is 44 km/h and suman's speed is 52 km/h, then at what time will they meet each other?

This questions was previously asked in

SSC MTS 12th October 2021 Shift-3

7 p.m

6 p.m

5 p.m

9 p.m

- Vaishnav starts his journey from place A toward place B at 11 a.m. with a speed of 44 km/h.

- By the time Suman leaves at 2 p.m., Vaishnav has already traveled for 3 hours.

- In those 3 hours, Vaishnav covers a distance of 44 * 3 = 132 km.

- So, the remaining distance between Vaishnav and Suman is 516 km - 132 km = 384 km.

- From 2 p.m., both are moving toward each other. Their combined speed is 44 km/h + 52 km/h = 96 km/h.

- They cover 384 km at 96 km/h, which takes 384 km / 96 km/h = 4 hours.

- Adding 4 hours to 2 p.m. gives 6 p.m. as their meeting time.

6 p.m. is the correct answer.

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