send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
If the ratio of the mode and median of a certain data is 9 : 8, then the ratio of its mean and median is:
15 : 17
13 : 15
15 : 16
11 : 15
- Let’s analyze the given ratios.
- The mode to median ratio is \( \frac{9}{8} \).
- Let's represent the median by \( M \). Then, the mode is \( \frac{9}{8}M \).
- We assume the simplest context where the arithmetic mean \( \mu \), median \( M \), and mode are related.
- For simplicity, assume values: Median \( M \), Mode \( \frac{9}{8}M \). Generally mean \( \mu \) is influenced by both.
- For balanced or symmetrically distributed data, mean \( \approx \) median.
- Trying out with simple cases: for validation \(\mu/M\), often mean would be aligned slightly differently around median due to presence of more extreme values.
- Option 3: 15 : 16 is interesting, think when median closely matches distribution symmetrically.
Option 3: 15 : 16 —
.
By: santosh ProfileResourcesReport error
Access to prime resources
New Courses