Two munbers A and B are respectively 20 and 56 more than a third number C The ratio of the numbers A...........

Quantitative Aptitude (MTS) Percentage

Two munbers A and B are, respectively, 20% and 56% more than a third number C. The ratio of the numbers A to B is:

This questions was previously asked in

SSC MTS 11th October 2021 Shift-2

10: 13

10: 17

11: l3

7 :11

- Let's define the third number C as the base value.

- Number A is 20% more than C. So, \( A = C + 0.2C = 1.2C \).

- Number B is 56% more than C. So, \( B = C + 0.56C = 1.56C \).

- To find the ratio of A to B, use the expressions for A and B: \( \frac{A}{B} = \frac{1.2C}{1.56C} \).

- Simplifying, the ratio becomes \( \frac{1.2}{1.56} = \frac{60}{78} \), which simplifies further to \( \frac{10}{13} \).

- Option 1: 10:13

- Option 2: 10:17

- Option 3: 11:13

- Option 4: 7:11

The correct ratio is 10:13. .

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