84 persons take 56 days to complete a ce11ain task When one fou11h of the task was completed one sev...........

Quantitative Aptitude (MTS) Time and work

84 persons take 56 days to complete a ce11ain task. When one-fou11h of the task was completed, one-seventh of the workers

left. How many days in all does it take to complete the entire task?

This questions was previously asked in

SSC MTS 6th October 2021 Shift-3

- 84 persons complete the entire task in 56 days.

- Rate of work = Total work / Total person days = 1/4704 of the task per day by one person.

- One-fourth of the task is completed in 14 days with 84 workers (84 x 14 x 1/4704 = 1/4 of the task).

- One-seventh of the workers leave means 72 workers remain.

- Remaining work is 3/4 of the task.

- Days needed for remaining work with 72 workers:

\( \text{Days} = \frac{(3/4) \times 4704}{72} = 49 \text{ days} \).

- Total days = 14 + 49 = 63 days.

- The correct answer is Option: 4 - 63.

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