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The average of 18 numbers is 65. The average of the first 10 numbers is 72 and that of the last 9 numbers is 58. If the 10th
number is excluded, then what is the average of the remaining numbers (correct to one decimal place)?
64.6
66.5
65.2
65.4
- The total sum of 18 numbers with an average of 65 is \( 18 \times 65 = 1170 \).
- The sum of the first ten numbers, with an average of 72, is \( 10 \times 72 = 720 \).
- The sum of the last nine numbers, with an average of 58, is \( 9 \times 58 = 522 \).
- We realize that the 10th number is counted twice in this arrangement of first 10 and last 9 numbers. So, calculate as follows:
$$
720 + 522 - 1170 = 72 \\
\text{Hence, the 10th number is 72.}
- If the 10th number is excluded, the calculation for the average becomes:
\left(\frac{1170 - 72}{17}\right) = 64.6
- Correct Answer: Option 1 - 64.6
By: santosh ProfileResourcesReport error
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