Let x be the least number between 70000 and 75000 which on being divided by 225 250 and 275 leaves a...........

Quantitative Aptitude (MTS) Number System

Let x be the least number between 70000 and 75000 which on being divided by 225, 250 and 275 leaves a remainder of 61 in each case. The sum of the digits of x is:

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SSC MTS 6th October 2021 Shift-3

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Explanation:

Correct Option is 3- 16

Given
Two given numbers are 70,000 and 75,000
Calculation
L.C.M of 225, 250 and 275 is 24,750 i.e. (5 x 5 x 3 x 3 x 10 x 11)
If 24,750 is multiply by 2 then it will be 49,500 which is less than 70,000
if 24,750 is multiply by 3, then it will be 74250. it is between the 70,000 and 75,000
so, Required number will be 74250+61= 74,311
sum of the digits of x is 7+4+3+1+1=16
-The sum of the digits of x is 16